Answer :
Probability of first getting a 3 = 4/52 = 1/13
The p(getting >2) = probability of getting one of the remaining 3's or 40 other cards ( Im taking the aces to be low value) = 43/51
Required probability = 1/13 * 43/51 = 43/663
If aces are counted high it will be 1/13 * 47/51 = 47/531
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The p(getting >2) = probability of getting one of the remaining 3's or 40 other cards ( Im taking the aces to be low value) = 43/51
Required probability = 1/13 * 43/51 = 43/663
If aces are counted high it will be 1/13 * 47/51 = 47/531
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