Answer :
You plug in the point in this equation :
y = 2x + b
4 = (2)-1 + b
Multiply the 2 by -1
4 = -2 + b
Add 2 to both sides
B = 6
We finally write our equation :
y = 2x + 6
y = 2x + b
4 = (2)-1 + b
Multiply the 2 by -1
4 = -2 + b
Add 2 to both sides
B = 6
We finally write our equation :
y = 2x + 6
For this case, the generic equation of the line is given by:
[tex]y-yo = m (x-xo) [/tex]
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line.
We have then that the slope of the line is:
[tex]m = 2 [/tex]
The line passes through the point (-1,4), therefore, the ordered pair is:
[tex](xo, yo) = (-1,4) [/tex]
Substituting values we have:
[tex]y-4 = 2 (x - (- 1)) [/tex]
Rewriting we have:
[tex]y-4 = 2 (x + 1) [/tex]
Answer:
An equation of the line that passes through the point (-1.4) with slope 2 is:
[tex]y-4 = 2 (x + 1)[/tex]
[tex]y-yo = m (x-xo) [/tex]
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line.
We have then that the slope of the line is:
[tex]m = 2 [/tex]
The line passes through the point (-1,4), therefore, the ordered pair is:
[tex](xo, yo) = (-1,4) [/tex]
Substituting values we have:
[tex]y-4 = 2 (x - (- 1)) [/tex]
Rewriting we have:
[tex]y-4 = 2 (x + 1) [/tex]
Answer:
An equation of the line that passes through the point (-1.4) with slope 2 is:
[tex]y-4 = 2 (x + 1)[/tex]