Answer :
let
x-------> workers in team one initially
y-------> workers in team two initially
we know that
x=2y-----> equation 1
(x-5)=(y-2)+7-----> x-5= y+5----> x=y+10---------> equation 2
equate equation 1 and equation 2
2y=y+10-----> y=10
x=2*10------> x=20
Team 1 now has 20-5 = 15 membersTeam 2 now hase 10-2 = 8 members
The Team 1 now has 15 members and Team 2 now has 8 members.
We have given that team one had twice as many workers as team two.
Let us consider,x workers in team one initially
y workers in team two initially.
we know that
[tex]x=2y.... 1[/tex]
Now next
[tex](x-5)=(y-2)+7\\ x-5= y+5\\x=y+10.........2[/tex]
We have to solve this equation by using substitution method
What is the substitution method for linear equation?
The substitution method functions by substituting the one y-value with the other.
Use the value of 1 in equation 2 we get
[tex]2y=y+10\\ 2y-y=10y=10x=2*10\\ x=20[/tex]
Therefore we have,
Team 1 now has 20-5 = 15 members
Team 2 now has 10-2 = 8 members
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