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Team one had twice as many workers as team two. The number of workers in team one is reduced by 5 and the number of workers in team two is reduced by 2. How many workers are there in each team now if there are 7 more workers in team one?

Answer :

calculista

let

x-------> workers in team one initially

y-------> workers in team two initially

we know that

x=2y-----> equation 1

(x-5)=(y-2)+7-----> x-5= y+5----> x=y+10---------> equation 2

equate equation 1 and equation 2

2y=y+10-----> y=10

x=2*10------> x=20

Team 1 now has 20-5 = 15 members 
Team 2 now hase 10-2 = 8 members


The Team 1 now has  15 members and Team 2 now has 8 members.

We have given that team one had twice as many workers as team two.

Let us consider,x workers in team one initially

y workers in team two initially.

we know that

[tex]x=2y.... 1[/tex]

Now next

[tex](x-5)=(y-2)+7\\ x-5= y+5\\x=y+10.........2[/tex]

We have to solve this equation by using substitution method

What is the substitution method for linear equation?

The substitution method functions by substituting the one y-value with the other.

Use the value of 1 in equation 2 we get

[tex]2y=y+10\\ 2y-y=10y=10x=2*10\\ x=20[/tex]

Therefore we have,

Team 1 now has 20-5 = 15 members

Team 2 now has 10-2 = 8 members

To learn more about the linear equation visit:

https://brainly.com/question/14323743

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