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Suppose a basketball player is an excellent free throw shooter and makes 94​% of his free throws​ (i.e., he has a 94​% chance of making a single free​ throw). assume that free throw shots are independent of one another. suppose this player gets to shoot three free throws. find the probability that he misses all three consecutive free throws. round to the nearest​ ten-thousandth.

Answer :

Probability of a failure on 1 throw = 1 - 0.94 = 0.06 or 6%.

Prob (he misses all 3) = 0.06^3 = 0.000216 = 0.0002 to nearest ten thousandth

The probability that he misses all three consecutive free throws will be 0.0002.

What is the probability?

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

Probability of success on 1 throw,P(s)  = 94 % = 0.94

Probability of failure on 1 throw;

P(f) = 1- P(s)

P(f) =1 - 0.94

P(f) =0.06

The probability of missing an n chance;

P(n) = [P(f)]³

P(n) =[0.06]³

P(n) = 0.000216

The value nearest ten-thousandth will be 0.0002.

Hence, the probability that he misses all three consecutive free throws will be 0.0002.

To learn more about probability, refer to the link: https://brainly.com/question/795909.

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