Answer :

grujan50

Angles  ∡DBE ≅ ∡ACD= 3x  reason - angles with parallel arms

Angles ∡ADC and ∡ADB=95° are supplemental angles which means

∡ADC + ∡ADB=180° => ∡ADC = 180° - ∡ADB= 180°-95°= 85°

In the triangle we have ∡ADC + ∡ACD + ∡CAD = 180° =>

85 + 3x + 2x = 180 => 85 + 5x = 180 => 5x= 180-85 => 5x=95

x=95/5 => x=19°

Good luck!!!

abidemiokin

The value of x from the given diagram is 19

The point where two lines meet is known as an angle.

From the given diagram, vector $A$ is parallel to vector BE

Due to this, mACD = mCBE = 3x (alternate interior angle)

Also, the sum of angle on the line BDC is 180 degrees

BDA + CDA = 180

95 + CDA = 180

CDA = 180 - 95

CDA = 85 degrees

From the triangle ACD, the sum of the interior angle of the triangle is 180 degrees. Hence:

ACD  + CAD + CDA = 180

3x + 2x + 85 = 180

5x = 180 - 85

5x = 95

x = 95/5

x = 19

Hence the value of x from the given diagram is 19.

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