Answer :
It has been given that,
NO + Ag⁺ → NO₃⁻ + Ag
The oxidation half reaction is,
NO + Ag⁺ = NO₃⁻ + Ag
The reduction half reaction is,
Ag⁺ +e⁻ → Ag
The overall balanced reaction is:
3Ag⁺ + NO + 2H₂O → 3Ag + NO₃⁻
Answer:
NO(g) + 2H2O(l) + 3Ag^+(aq)---------> NO3^-(aq) + 4H^+(aq) + 3Ag
Explanation:
Oxidation half equation
NO(g) + 2H2O(l)--------> NO3^-(aq) + 4H^+(aq). + 3e
Reduction half equation
3Ag^+(aq) + 3e--------> 3Ag
Overall reaction equation
NO(g) + 2H2O(l) + 3Ag^+(aq)---------> NO3^-(aq) + 4H^+(aq) + 3Ag