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A sinusoidal electromagnetic wave has a peak electric field of 8.00 kv/m. what is the intensity of the wave? (c = 3.0 × 108 m/s, μ0=4π × 10-7 t • m/a, ε0 = 8.85 × 10-12 c2/n • m2)

Answer :

E₀ = peak electric field = 8 kV/m = 8000 V/m

I = intensity of the electromagnetic wave = ?

c = speed of electromagnetic wave = 3 x 10⁸ m/s

μ₀ = 4π x 10⁻⁷ = 12.56 x 10⁻⁷

ε₀ = 8.85 x 10⁻¹²

intensity of the electromagnetic wave is given as

I = (0.5) ε₀ E²₀ c

inserting the values in the above equation

I = (0.5) (8.85 x 10⁻¹²) (8000)² (3 x 10⁸)

I = 8.5 x 10⁴ W/m²

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