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A person weighing 490N stands on a scale in an elevator. What does the scale read (normal force) when the elevator rises at a constant velocity of 5 m/s?

Answer :

skyluke89

Answer:

490 N

Explanation:

The elevator is rising at constant velocity: this means the acceleration of the system is zero, so according to Newton's second law, the net force on the system is also zero:

[tex]F_{net} = ma =0[/tex]

There are two forces acting on the person standing on the scale:

- its weight, downward, whose magnitude is W=490 N

- The normal force of the scale on the person, N, which is upward

Since the net force must be zero, we have:

[tex]W-N=0[/tex]

From which we find the normal force:

[tex]N=W=490 N[/tex]

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