Using Snell's Law:
n1 * sin(theta1) = n2 * sin(theta2)
where
n1 is the refractive index of the incident light (n1 = 1 in this case)
theta1 is the angle of incidence
n2 is the refractive index of the material that the light is entering (n2 = 1.53 in this case)
theta2 is the angle of refraction
n1 * sin(theta1) = n2 * sin(theta2)
becomes
1 * sin(60) = 1.53 * sin(theta2)
or
1 * 0.866 = 1.53 * sin(theta2)
0.866 = 1.53 * sin(theta2)
sin(theta2) = 0.866 / 1.53 = 0.566
theta2 = arcsin(0.566) = 34 degrees (the angle of refraction)
The angle of refraction is 34°.
To find the angle of refraction, the given values are:
Angle of incidence = 60°
Refractive index = 1.53
Snell's law can be defined as “the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given color for the given pair”.
Formula,
n₁ sin θ₁ = n₂ sin θ₂
n₁ = incident index
n₂ = refracted index
θ₁ = incident angle
θ₂ = refracted angle
Substituting the values of n₁ = 1, θ₁ = 60, n₂= 1.53
1 × sin (60) = 1.53 × sin θ₂
sin θ₂ = 0.866 / ( 1.53)
= 0.566
θ₂= sin ⁻¹ ( 0.566)
= 34°.
Hence, the angle of refraction is 34°.
Option C is the correct answer.
Learn more about Snell's law,
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