For this case we have by definition, that the derivative of the position with respect to time is the velocity, that is to say:
[tex]\frac {d (s (t))} {dt} = v (t)\\\frac {d (6-14t)} {dt} = v (t)[/tex]
So:
Taking into account that the derivative of a constant is 0.
[tex]\frac {d (6-14t)} {dt} = 0- (1 * 14 * t ^ {1-1}) = 0- (14 * t ^ 0) = - 14[/tex]
So, the velocity is -14
Answer:
-14
