Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis at five that ends at the open point 2, 5, a closed point at 2, 1, and another horizontal line starting at the open point 2, negative 2 and continues to the right. Find limit as x approaches two from the left of f of x. and limit as x approaches two from the right of f of x..

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis at five that ends at the open p class=

Answer :

Gasaqui

Answer:

The limit as x approaches 2 from the left of f(x) is 5

The limit as x approaches 2 from the right of f(x) is -2

Step-by-step explanation:

From the left, the coordinate graph shows a horizontal line crossing the y axis at five that ends at the open poing (2,5).

The limit as x approaches 2 from the left of f(x) is 5. Given that, from the left the graph approaches to 5.

From the right, the coordinate graph shoes a horizontal line starting at the open point (2, -2)  and continues to the right.

The limit as x approaches 2 from the right of f(x) is -2. Given that, from the right the graph approaches to 5.

luisejr77

Answer:

[tex]\lim_{x \to 2^-}f(x)=5[/tex]

[tex]\lim_{x \to 2^+}f(x)=-2[/tex]

Step-by-step explanation:

The graph of f(x) is that of a piecewise function that is composed of 2 horizontal lines and a point.

Notice in the graph that:

[tex]f(x) = 5[/tex] if [tex]x <2[/tex]

[tex]f(x) = 1[/tex] if [tex]x = 2[/tex]

[tex]f(x) = -2[/tex] if [tex]x> 2[/tex]

We must find the limit on the left of 2 and on the right of 2.

When we find the limit on the left of 2 it means that x is a value infinitesimally smaller than 2. Then [tex]x <2[/tex] .

Since x is less than 2 then f(x) tends to 5.

So

[tex]\lim_{x \to 2^-}f(x)\\\\=\lim_{x \to 2^-}5 = 5[/tex]

When we find the limit on the right of 2, it means that x is a value infinitesimally larger than 2. Then [tex]x> 2[/tex].

Since x is greater than 2 then f(x) tends to -2.

So

[tex]\lim_{x \to 2^+}f(x)\\\\=\lim_{x \to 2^+}-2 = -2[/tex]

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