Can someone please help me ASAP?

Answer:
b. 3
Step-by-step explanation:
Box J has surface area 2(4.5 ft * 2 ft) + 2(3 ft * 2 ft) + 2(4.5 ft * 3 ft) = 57
Box F has surface area 6(3^2 ft) = 54 ft^2
The difference between the surface areas is: 57 - 54 = 3
b. diff = 3
[tex]
S_j=2\cdot(3\cdot2)+2\cdot(4.5\cdot2)+2\cdot(4.5\cdot3) \\ S_j=12+18+27=\underline{57} \\ \\
S_f=6\cdot(3\cdot3)=6\cdot9=\underline{54} \\ \\
S_j-S_f=57-54=\boxed{3}
[/tex]
The answer is 3.