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A 50.0-mL sample of gas is cooled from 119ºC to 80.0ºC. If the pressure remains constant, what is the final volume of the gas?

Answer :

superman1987

Answer:

45.03 mL.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have different values of T and V:

(V₁T₂) = (V₂T₁).

V₁ = 50.0 mL, T₁ = 119ºC + 273 = 392 K,

V₂ = ??? mL, ​T₂ = 80ºC + 273 = 353 K.

∴ V₂ = (V₁T₂)/(T₁) = (50.0 mL)(353 K)/(392 K) = 45.03 mL.

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