Answer :
Answer:
[tex]y+6=m(x+2)[/tex]
where I would have to look at the table to know [tex]m[/tex].
Step-by-step explanation:
Point-slope form of a line is
[tex]y-y_1=m(x-x_1)[/tex]
where [tex]m \text{ is the slope and } (x_1,y_1) \text{ is a point on that line}[/tex]
You are given [tex](x_1,y_1)=(-2,-6) \text{, but no value for }m[/tex].
So we know we are looking for an equation that looks like this:
[tex]y-(-6)=m(x-(-2))[/tex]
If you simplify this looks like:
[tex]y+6=m(x+2)[/tex]