Answer :
Answer:
e = 0.97
[tex]\gamma = 25.859\ gm/cm^3[/tex]
Explanation:
Given data:
saturation value S = 50%
Specific gravity. G = 2.71
W, water content = 18%
void ratio [tex]e = \frac{wGs}{S}[/tex]
[tex]= \frac{ 18\times 2.71}{50}[/tex]
e = 0.97
Dry unit weight [tex] \gamma_d = \frac{Gs \gamma_w}{1+e}[/tex]
where [tex] \gamma_w[/tex] is unit weight of water is 0.99
[tex] = \frac{2.71\times 0.99}{1+0.97} [/tex]
[tex] = 1.361 gm/cm^3[/tex]
[tex]\gamma = \gamma_d (1 + w)[/tex]
[tex]= 1.361 (1+ 18)[/tex]
[tex] = 1.361 \times 19[/tex]
[tex]= 25.859\ gm/cm^3[/tex]