Answer:
All three operations lead to polynomials.
See explanations below.
Step-by-step explanation:
Polynomial a = [tex]3x^2(x-1)=3x^3-3x^2[/tex]
Polynomial b = [tex]-3x^3+4x^2-2x+1[/tex]
Therefore:
a + b = [tex]3x^3-3x^2+(-3x^3+4x^2-2x+1)=\\=3x^3-3x^2-3x^3+4x^2-2x+1=\\=x^2-2x+1[/tex]
where we have combined all like terms. This is clearly another polynomial (of grade 2)
a - b (here we need to flip all signs inside the parenthesis when we remove this grouping symbol):[tex]3x^3-3x^2-(-3x^3+4x^2-2x+1)=\\3x^3-3x^2+3x^3-4x^2+2x-1=\\6x^3-7x^2+2x-1[/tex]
which is clearly another polynomial (but of grade 3)
a * b : (here we use distributive property to multiply each term of the first polynomial by each term of the second one, and then combine like terms)
[tex](3x^3-3x^2)*(-3x^3+4x^2-2x+1)=\\-9x^6+12x^5-6x^4+3x^3+9x^5-12x^4+6x^3-3x^2=\\-9x^6+21x^5-18x^4+9x^3-3x^2[/tex] which is indeed another polynomial (this time of grade 6)
