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What is the slope-intercept form of the equation of the line with the slope of -5/8 that passes through the point (-14,6)

Answer :

bethclash23

Step-by-step explanation:

y-y1 = m(x-x1) is the equation for a linear line in y=mx+b (slope intercept)

slope = m = -5/8

x1 = -14

y1 = 6

y-6 = -5/8 (x--14)

y-6 = -5/8 (x+14)

y-6 = -5/8x-70/8

y-48/8= -5/8x-70/8

y = -5/8x - 22/8

When x = 0, y = -22/8, which makes (0, -22/8) your y intercept

Answer:

Step-by-step explanation:y-y1 = m(x-x1) is the equation for a linear line in y=mx+b (slope intercept)

slope = m = -5/8

x1 = -14

y1 = 6

y-6 = -5/8 (x--14)

y-6 = -5/8 (x+14)

y-6 = -5/8x-70/8

y-48/8= -5/8x-70/8

y = -5/8x - 22/8

When x = 0, y = -22/8, which makes (0, -22/8) your y intercept

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