[tex]\frac{1}{2}[/tex] of the grandmother's lawn Dan can mow per gallon.
Option C
Solution:
Given that, mowing [tex]\frac{1}{4}[/tex] uses [tex]\frac{1}{2}[/tex] gallon of gas.
To find: The fraction of the lawn can Dan mow per gallon
According to unitary method,
[tex]\frac{1}{2}[/tex] gallon of gas is required to mow [tex]\frac{1}{4}[/tex] of lawn that is [tex]\frac{1}{2}\rightarrow \frac{1}{4}[/tex]
Therefore, 1 gallon of gas will be required to mow [tex]\frac{1}{2}\times2\rightarrow \frac{1}{4}\frac2[/tex]
[tex]\Rightarrow1 \text{ gallon }\rightarrow \frac{1}{2} \text{ of lawn}[/tex]
Therefore, one gallon will be enough to mow [tex]\frac{1}{2}[/tex] of lawn.
Unitary method:
The unitary method is a technique to solve a problem by finding the value of a single unit first, and then finding the required value by multiplying the single unit value. In essence, this method is used to find the value of a unit from the value of a multiple, and hence the value of a multiple.
