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When ethane C2H6) burns, it produces carbon dioxide and water:
2C3H5(0) +702(g) → 4CO2(g) + 6H2011)
How many liters of carbon dioxide will be produced when 269 L of ethane are
burned? (One mole of any gas occupies 22.4 L under certain conditions of
temperature and pressure. Assume those conditions for this question.)

Answer :

Answer:

538L of carbon dioxide will be produced

Explanation:

This is a classic example of combustion of an alkane.

If balanced equation is not given; this format can come in handy.

For any alkane of the type : CₙH₂ₙ₊₂ , it's combustion reaction will follow:

2CₙH₂ₙ₊₂ + (3n+1) O₂  →  (2n)CO₂ + 2(n+1) H₂O

For ethane:

2C₂H₆(g) + 7O₂(g) →  4CO₂(g) + 6H₂O(l)

Here, 2 mole of ethane gives 4 moles of CO₂.

or, [tex]2 \times 22.4L[/tex] of ethane gives [tex]4 \times 22.4L[/tex] of CO₂.

Then, 269L of ethane will give:

= [tex]\frac{269 \times 4 \times 22.4}{2 \times 22.4}[/tex]

= [tex]269 \times 2[/tex] L

= 538 L

Therefore, 538L of carbon dioxide will be produced

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