Answer:
The first is a solution, but the second is not
Step-by-step explanation:
we know that
If a ordered pair is a solution of a linear equation, then the ordered pair must satisfy the linear equation (makes the equation true)
we have
[tex]5x-\frac{y}{3}=13[/tex]
Verify the first ordered pair
Part a) we have (2,-9)
For x=2, y=-9
substitute in the linear equation
[tex]5(2)-\frac{(-9)}{3}=13[/tex]
[tex]10-(-3)=13[/tex]
[tex]10+3=13[/tex]
[tex]13=13[/tex] ----> is true
so
The ordered pair satisfy the equation
The ordered pair is a solution of the equation
Verify the second ordered pair
Part b) we have (3,-6)
For x=3, y=-6
substitute in the linear equation
[tex]5(3)-\frac{(-6)}{3}=13[/tex]
[tex]15-(-2)=13[/tex]
[tex]15+2=13[/tex]
[tex]17=13[/tex] ----> is not true
so
The ordered pair not satisfy the equation
The ordered pair is not a solution of the equation
