Answer :
Answer:
0.80
Explanation:
- Compounded interest annually
[tex]I=P[(1+r)^n-1]\\I=100[(1+0.07)^5-1]\\\\I=100[1.40255173-1]\\I=100[.40255173]\\I=40.255173[/tex]
- Compounded interest Semiannually
[tex]I=P[(1+r)^n-1]\\I=100[(1+0.035)^{10}-1]\\\\I=100[1.41059876-1]\\I=100[.41059876]\\I=41.059876[/tex]
Difference between interest = 41.059876 - 40.255173
Difference between interest = 0.804703