Area of the figure = 112 in²
Solution:
The given figure is splitted into two shapes.
One shape is square.
Each side of square are equal.
Side = 10 inch
Area of the square = side × side
= 10 × 10
= 100
Area of the square = 100 in²
The other shape is triangle.
Base of the triangle = 10 in – 6 in = 4 inch
Height of the triangle = 16 in – 10 in = 6 inch
Area of the triangle = [tex]\frac{1}{2}\times \text{base}\times \text{height }[/tex]
[tex]$=\frac{1}{2}\times4\times6[/tex]
= 12
Area of the triangle = 12 in²
Area of the figure = Area of the square + Area of the triangle
= 100 in² + 12 in²
Area of the figure = 112 in²
Therefore, area of the given figure is 112 in².
