Answered

Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for several seconds. The player began counting at 0 seconds, even though the video had already played 190
frames. The video plays 25 frames per second.
How many frames had the video already played when the time was equal to [- 3 2/5] seconds?

Answer :

shaniah23

Answer:

105 frames

Step-by-step explanation:

Given that 25 frames are played per second

25 frames= 1 sec

The video already played 3 and 2/5 seconds before the player started to count 0

Write 3 and 2/5 seconds as an improper fraction

=(5*3)+2 / 5 = 17/5 seconds

Multiply by 25 frames

17/5 *25 =85 frames

So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.

190-85=105 frames

Answer:

105 frames.

Step-by-step explanation:

The rate of the video play is

  • 25 frames per second.

First, we need to transform the mixed number into a fraction

[tex]3\frac{2}{5}sec=\frac{17}{5}sec[/tex]

Now, using the rate, we can find the number of frames after 17/5 seconds

[tex]25 frames/second(\frac{17}{5}sec )=85 \ frames[/tex]

But, according to the problem, at 0 seconds, the video had already played 190 frames, so we need to find the difference

[tex]190 - 85 = 105 \ frames[/tex]

Therefore, the total number of frames after 3 2/5 seconds is 105.

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