Answer :
Answer:
The final stored energy will become half.
Explanation:
We know that stored energy in the capacitor is given as
[tex]E=\dfrac{1}{2}CV^2[/tex]
C=capacitance
V=Voltage difference
E=Energy
[tex]C=\dfrac{\varepsilon A}{d}[/tex]
d=Distance between plates
A=Area
[tex]E=\dfrac{1}{2}\times \dfrac{\varepsilon A}{d}\times V^2[/tex]
If the distance between plates get double ,say d' = 2 d
Then stored energy
[tex]E'=\dfrac{1}{2}\times \dfrac{\varepsilon A}{d'}\times V^2[/tex]
[tex]E'=\dfrac{1}{2}\times \dfrac{\varepsilon A}{2d}\times V^2[/tex]
[tex]E'=\dfrac {E}{2}[/tex]
Therefore the final stored energy will become half.