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Today at 10:56 AM
Chemistry

Answered

2B(s) + 3F2(g) 2BF3(g).

Which equilibrium expression is correct?

Answer :

Willchemistry Willchemistry

Today at 11:02 AM

2 B(s) + 3 F₂(g) = 2 BF₃(g)

Kc = products / reagents

Kc = [ BF₃ ]² / [ B ]² . [ F₂ ]³

hope this helps!

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