Answer :
Answer:
Michael buys 60 kg of dark chocolate and 40 kg of milk chocolate.
Step-by-step explanation:
Let d be the number of kilograms of dark chocolate Michael buys and m be the number of kilograms of milk chocolate he buys.
He needs to buy 100 kg of chocolate in total, then
[tex]d+m=100[/tex]
Dark chocolate costs $12 per kilogram, then d kg cost $12d. Milk chocolate costs $10 per kilogram, then m kg cost $10m. Michael wants to spend $1,120 for the chocolate, then
[tex]12d+10m=1,120[/tex]
From the first equation
[tex]d=100-m[/tex]
Substitute it into the second equation:
[tex]12(100-m)+10m=1,120\\ \\1,200-12m+10m=1,120\\ \\-12m+10m=1,120-1,200\\ \\-2m=-80\\ \\m=40\\ \\d=100-m=100-40=60[/tex]
Michael buys 60 kg of dark chocolate and 40 kg of milk chocolate.
Answer:
Michael uses a blend of dark chocolate and milk chocolate to make the ice cream topping at his restaurant. He needs to buy 100\,\text{kg}100kg100, start text, k, g, end text of chocolate in total for his next order. Dark chocolate costs \$12$12dollar sign, 12 per kilogram, milk chocolate costs \$10$10dollar sign, 10 per kilogram, and he wants to spend \$1120$1120dollar sign, 1120 total.
Let ddd be the number of kilograms of dark chocolate he buys and mmm be the number of kilograms of milk chocolate he buys.
Which system of equations represents this situation?
ANSWER:
CORRECT (SELECTED)
⎪d+m=100
⎨12d+10m=1120