Answered

2.00 × 10 − 3 mol of potassium ions pass through a cell membrane in 4.00 × 10 − 2 s. (a) Calculate the electric current and (b) describe its direction relative to the motion of the potassium ions

Answer :

Explanation:

(a)  The given data is as follows.

          Number of moles of potassium = 0.002 mol

          time = [tex]4.0 \times 10^{-2} sec[/tex]

First, we will calculate the number of ions as follows.

          No. of ions = [tex]0.002 \times 6.023 \times 10^{23}[/tex]

                             = 0.012 mol

Charge will be calculated as follows.

   q = [tex]0.002 \times 6.022 \times 10^{23} \times 1.6 \times 10^{-19}[/tex]

       = [tex]0.019 \times 10^{4}[/tex]

Hence, we will calculate the current as follows.

               Current = [tex]\frac{q}{t}[/tex]

                             = [tex]\frac{0.019 \times 10^{4}}{0.04 sec}[/tex]

                             = 4750 Ampere

Thus, we can conclude that electric current 4750 ampere.

(b)  As we know that current is the flow of electrons or ions. Therefore, the direction in which potassium ions will flow will also be the direction of electric current.

Other Questions