There are 10 rolls of film in a box and 3 are defective. Two rolls are to be selected without replacement. What is the probability of selecting a defective roll followed by another defective roll?

Answer :

JeanaShupp

Answer:   [tex]\dfrac{1}{15}[/tex]

Step-by-step explanation:

Given : Total rolls of film in the box = 10

Defective rolls =3

Probability of selecting first defective roll = [tex]\dfrac{\text{Number of bad rolls}}{\text{Total rolls}}[/tex]

[tex]=\dfrac{3}{10}[/tex]

Now , total rolls left = 9

Total defective rolls left = 2

Probability of selecting second defective roll = [tex]\dfrac{\text{Number of bad rolls}}{\text{Total rolls}}[/tex]

[tex]=\dfrac{2}{9}[/tex]

Now , the probability of selecting a defective roll followed by another defective roll = [tex]\dfrac{3}{10}\times\dfrac{2}{9}=\dfrac{1}{15}[/tex]

Hence, the probability of selecting a defective roll followed by another defective roll is [tex]\dfrac{1}{15}[/tex] .

Other Questions