The average number of transactions made at an ATM in a 20 minute period is 10. Use an appropriate probability distribution to find the probability that exactly 6 transactions will be made at an ATM in the next 20 minutes. Answer to four decimal places.

Answer :

Answer:

The probability that exactly 6 transactions will be made at an ATM in the next 20 minutes = 0.06306 = 0.0631 to 4d.p

Step-by-step explanation:

This is a Poisson distribution problem

The Poisson distribution formula is given as

P(X = x) = (e^-λ)(λˣ)/x!

where λ = mean = 10 transactions per 20 minutes

x = variable whose probability is required = 6 transactions in the next 20 minutes

P(X = 6) = (e⁻¹⁰)(10⁶)/6! = 0.06306

The probability that exactly 6 transactions will be made at an ATM in the next 20 minutes is 0.0630.

What is the Poisson distribution?

A Poisson distribution is a probability distribution that is used to show how many times an event is likely to occur over a specified period.

The formula for Poisson distribution is given as,

[tex]P(X) = \dfrac{e^{-\lambda}\times \lambda ^ {x}}{x!}[/tex]

Given that 10 transactions were made in 20 minutes. We need to find the probability for 6 transactions in 20 minutes. So,

[tex]\lambda = 10[/tex] and [tex]x = 6[/tex]

The probability is,

[tex]P(X) = \dfrac{e^{-10}\times 10^6}{6!}[/tex]

[tex]P(X) = \dfrac { 45.399}{720}[/tex]

[tex]P(X) = 0.0630[/tex]

Hence we can conclude that the probability that exactly 6 transactions will be made at an ATM in the next 20 minutes is 0.0630.

To know more about Poisson Distribution, follow the link given below.

https://brainly.com/question/5673802.

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