Answer:
[tex]f(x)=(x+3)^{2}-20[/tex]
Step-by-step explanation:
we have
[tex]f(x)=x^{2}+6x-11[/tex]
To convert to vertex form complete the square
[tex]f(x)=(x^{2}+6x+3^2)-11-3^2[/tex]
[tex]f(x)=(x^{2}+6x+9)-20[/tex]
Rewrite as perfect squares
[tex]f(x)=(x+3)^{2}-20[/tex] ----> equation in vertex form
The vertex is the point (-3,-20) (is a minimum)
