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Point X is the incenter of ΔABC.

Triangle A B C has point X as its incenter. Lines are drawn from the points of the triangle to point X. Lines are drawn from point X to the sides of the triangle to form right angles. Line segments X F, X G, and X E are formed.
If EX = 4z + 1, XF = 2z + 7, and mABC = 44°, find the following measures.

GX =

mABX =
°

Point X is the incenter of ΔABC. Triangle A B C has point X as its incenter. Lines are drawn from the points of the triangle to point X. Lines are drawn from po class=

Answer :

Answer: GX=13; mABX=22

Step-by-step explanation:

Set EX= 4z+1 and XF= 2z+7 equal time each other and then plug the answer to z and you’ll get GX=13, because EX=XF=GX are congruent. For mABX divide mABC by two to get the answer 22.

ankitprmr2

GX = 13

[tex]\rm \angle ABX = 22^ \circ[/tex]

Step-by-step explanation:

Given :

EX = 4z + 1  and XF = 2z + 7

Solution :

Take EX and XF equal time each other abd then solve for z and then you will get GX because EX = XF = GX are congruent.

EX = XF

4z + 1 = 2z + 7

2z = 6

z = 3

As,    EX = XF = GX

EX = 4(3) + 1

EX = 13

Therefore, GX = 13      ------      ( EX = XF = GX )

To find the [tex]\rm \angle ABX[/tex] , divide the [tex]\rm \angle ABC[/tex] by 2 you will get

[tex]\rm \angle ABX = 22^ \circ[/tex]

For more information, refer the link given below

https://brainly.com/question/16548605?referrer=searchResults

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