Answer:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer
Step-by-step explanation:
From the graph of the circle
∵ The center of the circle F is at the origin
∴ F is (0 , 0)
∵ The circle passes through point (7 , 0)
- The length of the radius of the circle is the distance between
the center of the circle and a point on the circle
∴ r is the distance between points (0 , 0) and (7 , 0)
∴ [tex]r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7[/tex]
∴ The length of the radius of the circle is 7 units
Let us find the distance between point (7 , -7) and the origin (0 , 0)
- If the distance is equal to the radius of the circle, then the point is on the circle
- If the distance is greater than the radius, then the point is outside the circle
- If the distance is less than the radius, then the point is inside the circle
∵ The distance = [tex]\sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}[/tex]
∵ r = 7
∵ [tex]7\sqrt{2}[/tex] > 7
∴ The distance is greater than the radius of the circle
∴ Point (7 , -7) lies outside the circle
The correct answer is:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle
Your answer is not correct, the correct answer is the 3rd answer
