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In three situations, a single force acts on a moving particle. Here are the velocities (at that instant) and the forces:
(1) v = (-4i^) m/s, F = (6i^ - 2j^) N
(2) v = (2i^ - 3j^) m/s, F = (-2j^ + 7k^) N
(3) v = (-3i^ + 1j^) m/s, F (2i^ + 6j^) N
Rank the situations according to the rate at which energy is being transferred, greatest transfer to the particle ranked first, greatest transfer from the particle ranked last.

Answer :

Answer:

The ranking is as follows : 2>3>1

Explanation:

In this case, we need to rank the situations according to the rate at which energy is being transferred, greatest transfer to the particle ranked first, greatest transfer from the particle ranked last.

Case 1.

[tex]v=(4i)\ m/s\ \text{and}\ F=(6i - 2j) N[/tex]

The rate at which energy is transferred is called power of an object. It is given by :

P = F.v

So,

[tex]P=(6i-2j){\cdot} (-4i)\\\\P=-24\ W[/tex]

Case 2,

[tex]v=(2i-3j)\ m/s\ \text{and}\ F=(-2j +7k) N[/tex]

Power :

[tex]P=(-2j+7k)\ {\cdot} (2i-3j)\\\\P=6\ W[/tex]

Case 3,

[tex]v=(-3i+1j)\ m/s\ \text{and}\ F=(2i +6j) N[/tex]

Power :

[tex]P=(2i+6j){\cdot} (-3i+1j)\\\\P=-6+6=0\ W[/tex]

So, it is clear that the power in second case is more than first and third case. So, the ranking is as follows : 2>3>1

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