. The Moon has a radius of 1.74×106m. It is orbiting the Earth at a distance of 3.84×108m, taking 27.3 days for a complete revolution. The free-fall acceleration on Moon is 1.62 m/s2 . From the information given, find the mass of the Moon and the mass of Earth.

Answer :

aabdulsamir

Answer: mass of moon = 7.350 * 10²² Kg

Mass of earth = 5.98 * 10²⁴Kg

Explanation:

acceleration due to gravity = (gravitational constant * mass of the body) / (distance from the centre of mass)²

g = Gm/r²

G = 6.673 * 10^-11

g(moon) = 1.62 m/s²

r (moon) = 1.74 *10⁶

g = GM/r²

M = gr² / G

M = 1.62 * (1.74 * 10⁶)² / 6.673 * 10^-11

M = 7.350 * 10²² Kg

Mass of moon = 7.350 * 10²² Kg

Mass of earth =?

g = GM / r²

M = gr² / G

g = 9.8 m/s²

G = 6.673 * 10 ^-11

r = 3.84 * 10⁸m

M = 9.8 * (3.84 * 10⁸)² / 6.673 * 10^-11

M = 5.98 * 10²⁴ Kg

Mass of the earth = 5.98 * 10²⁴kg

The answer to the given questions would be as follows:

Mass of the moon = [tex]7.350[/tex] × [tex]10^{22} Kg[/tex]

Mass of the Earth = [tex]5.98[/tex] × [tex]10^{24} Kg[/tex]

Find the gravity

As we know,

The acceleration caused through gravity:-

= [tex](gravitational constant[/tex] × [tex]mass of the body)/(distance from the center of[/tex] [tex]mass)^2[/tex]

Given that,

The radius of the moon(r) [tex]= 1.74[/tex] × [tex]10^6[/tex]

Distance [tex]= 3.84[/tex] × [tex]10^8[/tex]m

Time for a revolution [tex]= 27.3[/tex]

Acceleration on Moon(g) [tex]= 1.62 m/s^2[/tex]

Since Mass [tex]= gr^2 / G[/tex]

[tex]= 1.62[/tex] ×[tex](1.74[/tex] × [tex]10^6)^2 / 6.673[/tex] × [tex]10^{-11}[/tex]

Moon's mass [tex]=[/tex] [tex]7.350[/tex] × [tex]10^{22} Kg[/tex]

Since,

g(gravity [tex]= 9.8 m/s^2[/tex]

G(Gravitational constant)  [tex]= 6.673[/tex] × [tex]10^{-11}[/tex]

r(Radius) [tex]= 3.84[/tex] × [tex]10^8[/tex]m

Using the formula,

[tex]= 9.8[/tex] × [tex](3.84[/tex] × [tex]10^8)^2 / 6.673[/tex] ×  [tex]10^{-11}[/tex]

Earth's mass [tex]=[/tex] [tex]5.98[/tex] × [tex]10^{24} Kg[/tex]

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