Answer :
I will add + operators, because the equation is incomplete.
f(x) = x^2 + 2x + 3
To find the solution, complete a perfect square
f(x) = (x^2 + 2x + 3) -2 + 2
f(x) = (x^2 + 2x + 1) + 2
f(x) = (x + 1)^2 + 2
Answer: (x+1)^2 + 2
f(x) = x^2 + 2x + 3
To find the solution, complete a perfect square
f(x) = (x^2 + 2x + 3) -2 + 2
f(x) = (x^2 + 2x + 1) + 2
f(x) = (x + 1)^2 + 2
Answer: (x+1)^2 + 2
The quadratic equation f(x) = x^2 + 2x + 3 in vertex form is f(x) = (x + 1)^2 + 2
How to rewrite in standard form?
The equation is given as:
f(x) = x^2 + 2x + 3
Rewrite as:
f(x) = (x^2 + 2x) + 3
Take the coefficient of x
k = 2
Divide by 2
k/2 = 1
Square both sides
(k/2)^2 = 1
Rewrite the equation as:
f(x) = (x^2 + 2x + 1 - 1) + 3
This becomes
f(x) = (x^2 + 2x + 1) - 1 + 3
Express as a perfect square
f(x) = (x + 1)^2 - 1 + 3
Evaluate the difference
f(x) = (x + 1)^2 + 2
Hence, the equation in vertex form is f(x) = (x + 1)^2 + 2
Read more about vertex form at:
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