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Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Which student’s measurement has the largest percent error?

A. Student 4: 9.61 m/s2
B. Student 3: 9.88 m/s2
C. Student 2: 9.79 m/s2
D. Student 1: 9.78 m/s2

Answer :

ajeigbeibraheem

The student with the largest measurement of percentage error is student 4. Option A is correct.

The percent error shows the disparity between the observed value and the actual value. It is given by the expression:

[tex]\mathbf{ \% \ error= \dfrac{v_A -v_E}{v_E}\times 100\%}[/tex]

For student 4: the percentage error can be computed as:

[tex]\mathbf{ \% \ error= \dfrac{9.78 -9.61}{9.61}\times 100\%}[/tex]

[tex]\mathbf{ \% \ error= 1.77 \%}[/tex]

For student 3; the percentage error is:

[tex]\mathbf{ \% \ error= \dfrac{9.78 -9.88}{9.88}\times 100\%}[/tex]

[tex]\mathbf{ \% \ error= -1.01 \%}[/tex]

For student 2; the percentage error is:

[tex]\mathbf{ \% \ error= \dfrac{9.78 -9.79}{9.79}\times 100\%}[/tex]

[tex]\mathbf{ \% \ error= -0.10}[/tex]

For student 1; the percentage error is:

[tex]\mathbf{ \% \ error= \dfrac{9.78 -9.78}{9.78}\times 100\%}[/tex]

[tex]\mathbf{ \% \ error= 0}[/tex]

Therefore, we can conclude that the student's measurement that has the largest percent error is student 4.

Learn more about percentage error here:

https://brainly.com/question/4170313?referrer=searchResults

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