Answer :
Answer:
Weight W = 392.4 N
Density [tex]\rho[/tex] = 784.31 [tex]\frac{kg}{m^{3} }[/tex]
Specific gravity S = 0.78431
Force required F = 10 N
Explanation:
Given data
Mass (m) = 40 kg
Volume (V) = 0.051 [tex]m^{3}[/tex]
Weight W = m × g
⇒ W = 40 × 9.81
⇒ W = 392.4 N
This is the weight of the methanol.
Density [tex]\rho[/tex] = [tex]\frac{mass }{volume}[/tex]
⇒ [tex]\rho[/tex] = [tex]\frac{40}{0.051}[/tex]
⇒ [tex]\rho[/tex] = 784.31 [tex]\frac{kg}{m^{3} }[/tex]
This is the density of the methanol.
Specific gravity (S) = [tex]\frac{\rho}{\rho_{water} }[/tex]
⇒ [tex]S = \frac{784.31}{1000}[/tex]
⇒ S = 0.78431
This is the specific gravity of the methanol.
Force needed to accelerate this tank F = ma
⇒ F = 40 × 0.25
⇒ F = 10 N
This is the force required to accelerate the tank.