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A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . What is the electric force acting on the charge?

Answer :

opudodennis

Answer:

0.9N/C

Explanation:

-The force of a charged particle in an electric field is given by the equation;

[tex]F=qE\\\\q-charge\\[/tex]

#we substitute the values of the charge and field strength:

[tex]F=qE\\\\=4.5\times10^{-5}\times2.0\times10^4\\\\=0.9 \ N/C[/tex]

Hence, the electric force acting on the charge is 0.9N/C

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