Step-by-step explanation:
Given the equation
[tex]2x-y = -3[/tex]
[tex]y=2x+3[/tex]
Putting x = -2 in the equation
y = 2x + 3
= 2(-2) + 3
= -4 + 3
= -1
(x, y) = (-2, -1)
Putting x = -1 in the equation
y = 2x + 3
= 2(-1) + 3
= -2 + 3
= 1
(x, y) = (-1, 1)
Putting x = 0 in the equation
y = 2x + 3
= 2(0) + 3
= 0 + 3
= 3
(x, y) = (0, 3)
So the table chart of x and y values will be:
x y
-2 -1
-1 1
0 3
[tex]\mathrm{Slope-Intercept\:form\:of}\:2x-y=-3:\quad y=2x+3[/tex]
[tex]\mathrm{Slope\:of\:}2x+3:\quad m=2[/tex]
[tex]\mathrm{Y\:Intercepts}:\:\left(0,\:3\right)[/tex]
The graph of [tex]y=2x+3[/tex] is attache below.
Answer:
Sample Response/Explanation: Yes, the lines will intersect because the slopes are different. Also, both lines have a y-intercept of -7, so they both include the point (0, –7).
