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the graph of x^2+y^2=16 by drawing the line x+y=1 solve the equation x^2+y^2=16,x+y=1

Answer :

Answer:

The solution is : (0,1) and (1,0)

Step-by-step explanation:

We want to solve the system of equations by graphing.

The system is;

[tex] {x}^{2} + {y}^{2} = 1 \\ x + y = 1[/tex]

The first equation,

[tex] {x}^{2} + {y}^{2} = 1[/tex]

is the equation of a circle, with center at the origin and radius 1.

The second equation is x+y=1.

This rewrite in the form;

[tex]y = - x + 1[/tex]

This is a straight line with a negative slope and intercepts at x=1, y=1.

The two graphs are drawn on the same graph sheet as shown in the attachment.

The two graphs intersect at (0,1) and (1,0).

Therefore the solution is : (0,1) and (1,0)

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