Answer :
Answer:
[tex]-4760kgm/s[/tex]
Explanation:
[tex]56m/s[/tex] will be the man's speed when touch the snow, therefore:
[tex]v_{a} =56m/s[/tex]
The final velocity is zero
[tex]v_{b} =0m/s[/tex]
The mass:
[tex]m=85kg[/tex]
Now we can apply impulse relationship which stated that:
Δp=mΔv
Δp=[tex]m(v_{b} -v_{a} )[/tex]
substitute the values
Δp[tex]=85(0-56)[/tex]
Δp[tex]=-4760kgm/s[/tex] upward