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An 85 kg paratrooper once fell 370 m from an airplane without a working parachute. He landed in snow and suffered only minor injuries. Assume that the speed at impact was 56 m/s, terminal velocity, and that the force on him by the snow was at the survivable limit of 1.2×1051.2×105 N. What is the magnitude of the impulse on him from the snow? Enter your answer in kg m/s, but do not enter units.

Answer :

Answer:

[tex]-4760kgm/s[/tex]

Explanation:

[tex]56m/s[/tex]  will be the man's speed when touch the snow, therefore:

[tex]v_{a} =56m/s[/tex]

The final velocity is zero

[tex]v_{b} =0m/s[/tex]

The mass:

[tex]m=85kg[/tex]

Now we can apply impulse relationship which stated that:

Δp=mΔv

Δp=[tex]m(v_{b} -v_{a} )[/tex]

substitute the values

Δp[tex]=85(0-56)[/tex]

Δp[tex]=-4760kgm/s[/tex] upward

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