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Consider the following reaction in which all reactants and products are gases. 1.00 mol of A and 2.00 mol of B are placed in a 5.0-liter container. After equilibrium has been established, 0.50 mol of D is present in the container. Calculate the equilibrium constant, Kc, for the reaction.

Answer :

jamesesther1234

Answer:

The equilibrium constant for this reaction is = 1.25

Explanation:

The equation for this reaction is:

A + B → D

A = 1.0mol ⇒  {A}=1.0 mol/5.00 L = 0.2 M

B = 2.0 mol ⇒ [B] = 2.0 mol/5.00 L= 0.4 M

D = 0.5 mol ⇒ [D] = 0.5 mol/5.00 L = 0.1 M

[tex]K_{c} = \frac{[D]}{[A][B]}[/tex] = [tex]\frac{0.1}{0.4*0.2}[/tex] =1.25

The equilibrium constant for this reaction is = 1.25

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