Answer :
Answer:
465.69g KCIO3
Explanation:
See the stoichiometry in the reaction:
We can propose
3 moles of oxgen are made of 2 moles of chlorate
Therefore 5.70 moles of O₂ will be made by (5.70. 2) / 3 = 3.8 moles of chlorate.
We convert the moles to mass: 3.8 mol . 122.55 g/ 1 mol = 465.69g KCIO3
is the mass to use in the begining
Answer:
We have to start with 465.69 grams of KClO3 (option 4 is correct)
Explanation:
Step 1: Data given
Moles of O2 = 5.7 moles
Molar mass KClO3 = 122.55 g/mol
Step 2: The balanced equation
2KCIO3 → 2KCI + 3O2
Step 3: Calculate moles KClO3
For 2 moles KClO3 we'll have 2 moles KCl and 3 moles O2
For 5.7 moles O2 we nee 2/3 * 5.7 = 3.8 moles KClO3
Step 4: Calculate mass of KClO3
Mass KClO3 = moles KClO3 * molar mass KClO3
Mass KClO3 = 3.8 moles * 122.55 g/mol
Mass KClO3 = 465.69 grams
We have to start with 465.69 grams of KClO3 (option 4 is correct)