Answer:
Mass of Cu(NO₃)₂ produced = 125.67 g
limiting reactant = Cu
Explanation:
Given data:
Mass of Cu = 42.6 g
Mass of HNO₃ = 84.0 g
What is limiting reactant = ?
Mass of Cu(NO₃)₂ produced = ?
Solution:
Chemical equation:
3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 4H₂O + 2NO
Number of moles of Cu:
Number of moles = mass/ molar mass
Number of moles = 42.6 g/63.546 g/mol
Number of moles = 0.67 mol
Number of moles of HNO₃:
Number of moles = mass/ molar mass
Number of moles = 84 g/63.01 g/mol
Number of moles = 1.3 mol
Now we will compare the moles of Cu(NO₃)₂ with HNO₃ and Cu from balance chemical equation.
HNO₃ : Cu(NO₃)₂
8 : 3
1.3 : 3/8×1.3 = 6
Cu : Cu(NO₃)₂
3 : 3
0.67 : 0.67
Number of moles of Cu(NO₃)₂ produced by Cu are less so Cu will limiting reactant.
Mass of Cu(NO₃)₂:
Mass = number of moles × molar mass
Mass = 0.67 mol × 187.56 g/mol
Mass = 125.67 g
