Answer :
Hello,
We suppose 2x-1≠0 or x≠1/2
[tex] \dfrac{f(x)}{g(x)} = \dfrac{x(2x-1)}{2x-1} =x \\\\ [/tex]
We suppose 2x-1≠0 or x≠1/2
[tex] \dfrac{f(x)}{g(x)} = \dfrac{x(2x-1)}{2x-1} =x \\\\ [/tex]