Answered

When a certain paramagnetic material is placed in an external magnetic field of 1.50T , the field inside the material is measured to be 1.5023T .



Part A


The relative permeability of this material is


1.0015.


0.0015.


1.


10.015



Part B


The magnetic permeability of this material is


0T.m/A.


1.259.10?7T.m/A.


1.259.10?6T.m/A.


1.259.10?5T.m/A.

Answer :

Answer:

The relative permeability of material is 1.0015 and  magnetic permeability of material is [tex]1.259 \times 10^{-6}[/tex]

Explanation:

Part A:

Given:

Magnetic field in material [tex]B = 1.5023[/tex] T

Magnetic field in air [tex]B_{o} = 1.50[/tex] T

The relative permeability of material is given by,

    [tex]\mu _{r} = \frac{B}{B_{o} }[/tex]

    [tex]\mu _{r} = \frac{1.5023}{1.50}[/tex]

    [tex]\mu _{r} = 1.0015[/tex]

Part B:

The magnetic permeability of material is given by,

    [tex]\mu _{r} = \frac{\mu}{\mu _{o} }[/tex]

Where [tex]\mu _{o} = 4 \pi \times 10^{-7}[/tex]

  [tex]\mu = \mu _{r} \mu _{0}[/tex]

  [tex]\mu = 1.0015 \times 4 \pi \times 10^{-7}[/tex]

  [tex]\mu = 1.259 \times 10^{-6}[/tex]

Therefore, the relative permeability of material is 1.0015 and  magnetic permeability of material is [tex]1.259 \times 10^{-6}[/tex]

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