Answer :
Answer:
The angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .
Explanation:
Given :
Mass of pulley , m = 2 kg .
Radius of pulley , R = 0.1 m .
Angular velocity of pulley , [tex]\omega=2\ rad/s[/tex] .
We need to find the angular momentum
We know , angular momentum of a rigid body is given by :
[tex]L=I\omega[/tex] ......( 1 )
Here , I is the angular momentum of cylindrical pulley and is given by :
[tex]I=\dfrac{MR^2}{2}\\\\I=\dfrac{2\times 0.1^2}{2}\\\\I=0.01\ kg \ m^2[/tex]
Putting value of I and [tex]\omega[/tex] in equation 1 .
We get :
[tex]L=0.01\times 2\ kg\ m^2\ rad /s\\\\L=0.02 \ kg\ m^2\ rad /s\\[/tex]
Therefore , the angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .