Answer :
Answer:
solution given that
(h k)=(10 9)
r=3
then we know that
equatiin of circle with radius 3 unit and centre at (10 9)is
(x-h)^2+(y-k)^2=r^2
(x-10)^2+(y-9)^2=3^2
x^2-2×x×10+10^2+y^2-2×y×9+9^2=9
x^2-20x+100+y^2-18y+81=9
x^2+y^2-20x-18y+180=0ans