Answer :
Answer:
Correct option:
Fail to reject H₀. There is enough evidence at the 5% level of significance to support the claim.
Step-by-step explanation:
The claim to be tested is:
Claim: μ ≠ 0.
The information provided is:
α = 0.05
σ = 2.62
Sample statistics: = -0.69
n = 60
As the population standard deviation is provided, it can be determined that a z-test for single is used to performed the test.
Decision rule:
If the p-value of the test is less than the significance level, α then the null hypothesis will be rejected and vice-versa.
Compute the p-value as follows:
[tex]p-value=2P(Z<-0.69)\\=2\times [1-P(Z<0.69)]\\=2\times [1-0.7549]\\=0.4902[/tex]
*Use a z-table for the probability.
The p-value = 0.4902 > α = 0.05.
The null hypothesis was failed to rejected at 5% level of significance.Thus, it can be concluded that there is enough evidence at the 5% level of significance to support the claim.