Answer :
Answer:
[tex]\frac{x^2}{16} -\frac{y^2}{65} = 1[/tex]
Step-by-step explanation:
standard form is :
[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\\[/tex]
where the vertice is (+-a,0), and foci is (+-c,0) and c^2 = a^2 + b^2
Answer:
[tex]\frac{x^2}{16} -\frac{y^2}{65} = 1[/tex]
Step-by-step explanation:
standard form is :
[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\\[/tex]
where the vertice is (+-a,0), and foci is (+-c,0) and c^2 = a^2 + b^2